How do i rationalize the dominator and simplify for the square root of 35 over the square root of 55?

Question

How do i rationalize the dominator and simplify for the square root of 35 over the square root of 55?

Answer 1

√35/√55

first cancel out the √5

√7/√11

multiply top and bottom by √11

(√77)/11

.

Answer 2

sqrt(35)/sqrt(55)=sqrt(5)*sqrt(7)/(sqrt(... * sqrt(11)/sqrt(11) = sqrt(7)*sqrt(11)/11 = sqrt(77)/11

Answer 3

√35/√55=

√(35/55)=

√(7/11)=

√7/√11 *√11/√11=

√(7*11)/11=(√77)/11

Answer 4

To rationalize a denominator if it has a square root in it, simply multiply the numerator and denominator by that square root and then simplify:

sqrt35 / sqrt55 (multiply numerator and denominator by sqrt55)

sqrt35 * sqrt55 / 55

sqrt1925 / 55

sqrt(77*25) / 55

5sqrt77 / 55

sqrt77 / 11 <===ANSWER

Answer 5

√35/√55 is simplified first by multiplying num. and denom. by √55

= √35 * √55 / 55

Now carry out the multiplication and extract as many squares as possible (there's only one)

= √1925 / 55 = √(25 * 77) / 55 = 5√77 / 55

= √77 / 11