Question:

How do i solve (4+8i)^2?

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  1. (4+8i)^2

    = 16 + 64i + (-64)

    = - 48 + 64i

    　

    　


  2. (4+8i)²

    multiply it out

    16 + 2*4*8i + 64i²

    16 + 64i - 64

    - 48 + 64i

    .


  3. (a+b)^2 = a^2 + 2ab + b^2



    Therefore, (4+8i)^2 = 16 + 64i + 64i^2

  4. (4 + 8 i) (4 + 8 i)

    16 + 64 i + 64 i²

    16 + 64 i - 64

    - 48 + 64 i

    PS

    The word "Solve" is used for equations ie an = sign is required.

  5. (4 + 8i)^2

    (4 + 8i)(4 + 8i) FOIL

    16 + 64i + 64i^2 Rule states, "i^2 = -1

    16 + 64i + 64(-1) Simplify

    16 + 64i - 64

    -48 + 64i ANSWER
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