How do i solve. 6x²+10x+4=0?

Question

Somehow i managed to end up with answers of 1/3 and -2. Please tell me what i'm doing wrong

Answer 1

x=-11.5

46/4=-11.5

m pretty sure im right.

Answer 2

(2x+2)(3x+2)=0

x=-1,-2/3

Answer 3

What you did was 6x²+10x-4 = 0.

6x²+10x-4 = 2(3x^2+5x-2) = 2(3x-1)(x+2) = 0

x = 1/3, -2

6x²+10x+4 = 2(3x^2+5x+2) = 2(3x+2)(x+1) = 0

x = -2/3, -1

Answer 4

(3x + 2)(2x + 2) = 0

x = - 2/3 , x = - 1

Answer 5

1) 6x²+10x+4=0

2) 2(3x² + 5x +2) = 0

3) 2(3x + 2)(x +1) = 0

4) 3x + 2 = 0

     x = -2/3

5) x + 1= 0

    x = -1

x = -2/3 and -1

Answer 6

The first step you can do is simplify. A common thing you can factor out is 2.

2(3x^2 + 5x + 2) = 0

3x^2 + 5x + 2 = 0

You then use the quadratic formula x = (-b (+/-) (square root b^2 - 4ac))/2a.

Your answers should be...

x = -2/3 and -1

Answer 7

6x^2 + 10x + 4 = 0

2[ 3x^2 + 5x +2] = 0

3x^2 + 3x + 2x + 2 = 0

3x(x + 1) + 2( x + 1) =0

(3x+2)(x+1) =0

x = -2/3 ; x = -1

Answer 8

6x²+10x-4 = 2(3x^2+5x-2) = 2(3x-1)(x+2) = 0

x = 1/3, -2

6x²+10x+4 = 2(3x^2+5x+2) = 2(3x+2)(x+1) = 0

x = -2/3, -1

Answer 9

Divide by 2 , you get 3X^2 + 5X + 2 =0,delta=25-24=1,X1=-2 & X2=-4/3

see your college lgebra for the quadradic formulla.

Answer 10

well you factor it

notice that 2 goes into all 3 numbers(6,10,4)

so divide all 3 by 2

then you end up with

3x(squared)+5x+2=0

your trying to find 2 numbers that multiply to get 6 and add up to get 5

those numbers are 3 and 2

so you replace 5x with 3x and 2x

so then you have 3x(squared)+3x+2x+2

then you have a binomial

(3xsquared+3x) + (2x+2)=0

then you take a 3x from the first parenthaseis, and 2 from the second parenthaseis

now you have

(x+1)+(x+1)=0

you set each parenthaseis equal to 0

x+1=0

subtract 1 from each side and 1 answer is x= -1

then you do the other one

x+1=0

subtract 1 from each side and the other answer is x= -1

so your answers are -1 and -1