Question:

How do i work out this sum???

by  |  earlier

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Substitute a=5, b=-4, c=11.

3b squared -5a squared c/4b

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  1. [3(-4)]^2 – [5 (5)]^2 * 11

                4(-4)

    = -144  - 625 *11/-16

    =330.69


  2. i am not completely sure but i think:

    (3 times-4) multiply then square it . but if there exist no parentheses then u just square the "b" then u multiply it to 3

    think : Parentheses, exponent/powers, multiply*, divide*, add, subtract

    * multiply and divide can be done in either order from left to right

  3. r those three different problems or are they all in one problem??..is it:

    3b^2-5b^2 ? c/4b I am a little confused

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