How do u do this equation step by step?

Question

x(2x-5)=12

Answer 1

x*2x -5x = 12

2x^2 - 5x -12 = 0

(2x + 3)(x - 4) = 0

Solve each side for 0 (if one is 0, the equation holds true.

x = 4

x = -3/2

Answer 2

expand,2x^2-5x=12   then bring the 12 to left side

2x^2-5x-12=0  solve by factorizing  2*12=24 an -12 soo think of a number u multiply twice which gives 24 an then u add which gives -12

  but it would not work so use fromular method an substitute

a=2,b=-5,c=-12 (-b plus or minus root of b^2-4ac)/2a

Answer 3

x(2x-5)=12

try to distribute x first:

2x(x) {it is supposed to be two x squared} -5x = 12

then transpose 12 making it

2x(x) - 5x - 12=0

then do the quadratic formula

x= (- b +/-square root of b squared - 4(a)(c)) / 2a

=5 +/- square root of 25-4(2)(-12) / 2(2)

=5 +/- square root of 25- (-96) / 4

=5 +/- square root of 121 / 4

=5 +/- 11/4

=5+11 / 4

=16 /4

=4

0r = 5 - 11 /4

    = -6/4

    = -3/2