How do u solve: 7y=2x+35 and 3y=2x+15?

Question

the equations are both one problem as in one on top of the other like linear equations.

Answer 1

21y = 6x + 105

21y = 14x + 105

6x + 105 = 14x + 105

x = 0

y = 5

Answer 2

7y = 2x + 35 and 3y = 2x + 15

7y = 2x + 35........y = (2x + 35)/7

3y = 2x + 15........y = (2x + 15)/3

(2x + 35)/7 = (2x + 15)/3

3(2x + 35) = 7(2x + 15)

6x + 105 = 14x + 105

105 = 8x + 105

0 = 8x

0 = x

y = (2x+ 35)/7

y = (2(0) + 35)/7

y = 35/7

y = 5

(0, 5) = Final Answer

Answer 3

2x = 7y-35 and 2x = 3y-15

So, 7y-35 = 3y - 15

4y = 20

y = 5

So x = (7*5 -35)/2 = 0