How do you Put the equation in standard form for an ellipse? Need help now!!!?

Question

16x^2 - 32x + 25y^2 + 50y = 359

Answer 1

complete the square...and then u get

16 (x^2 - 2x + 1 - 1) + 25(y^2 + 2y + 1 - 1) = 359

16(x-1)^2 + 25(y+1)^2 -16 - 25 = 359

16(x-1)^2 + 25(y+1)^2 = 400

(x-1)^2 / 25   + (y+1)^2 / 16  = 1

thats it

Answer 2

complete the square on the terms involving x & y...[x-a]² / [ 400/16] + [y-b]² / [ 400/25] = 1....you find a & b, it is not hard...gads 'scrander' it is +16 and +25!!

Answer 3

16x² - 32x + 25y² + 50y = 359

16(x² - 2x + 1) + 25(y² + 2y + 1) = 359 - 16 - 25

16(x - 1)² + 25(y + 1)² = 318

16(x - 1)² / 318 + 25(y + 1)² /318 = 1

8(x - 1)²/159 + 25(y + 1)² /318 = 1

Answer 4

Scrander above is right except when you complete the square because whatever you add you have to take away inside the parantheses.

16[x^2 - 2x + 1 (- 1)] + 25[x^2 + 2y + 1 (- 1)] = 359

16(x -1)^2 -16 + 25(y+1)^2 -25 = 359

16(x -1)^2 + 25(y+1)^2 = 400

___(x-1)^2____    +   ____(y+1)^2____   =   1

,,,,,,,,25,,,,,,,,,,,,,,,,,         ,,16  ,

mind the commas