Question:

How do you calculate the energy released when 24.8g Na2O reacts in the following reaction..?

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calculate the energy released when 24.8g Na2O reacts in the following reaction. Na2O(s) + 2HI(g) --> 2NaI(s) + H2O(l) (Na = 23 amu; O = 16 amu)?

a. 2.42 kcal

b. 3.00 x 10^2 kcal

c. 48.0 kcal

d. 0.207 kcal

i have such a hard time understanding even the simple stuff in chemistryyy!!! :( HELP

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  1. hey...it would be better if you submitted this question in the chemistry section.  You would have much better results.

    I may be able to help... I know you need to convert grams to moles.  Also, you will use moles ratios.

    Try visiting websites dealing with thermochemisty.

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