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calculate the energy released when 24.8g Na2O reacts in the following reaction. Na2O(s) + 2HI(g) --> 2NaI(s) + H2O(l) (Na = 23 amu; O = 16 amu)?a. 2.42 kcalb. 3.00 x 10^2 kcalc. 48.0 kcald. 0.207 kcali have such a hard time understanding even the simple stuff in chemistryyy!!! :( HELP
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