How do you calculate the number of ions in a strong electrolyte?

Question

such as 100.0 mL of 0.100 M NaOH

Answer 1

0.1L (0.1M) = 0.01 moles

0.01 moles X Avogadro's # = molecules NaOH

molecules NaOH = ions Na+

molecules NaOH = ions OH-

molecules NaOH X 2 = total ions (if nothing else considered present)