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How do you calculate the number of moles of O atoms in 7.77g of Mn(NO3)2?

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How do you calculate the number of moles of O atoms in 7.77g of Mn(NO3)2?

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  1. 7.77g Mn(NO3)2 * (1 mol/ molar mass of Mn(no3)2) * ( 6 mol O/ 1 mol Mn(no3)2) * (1 mol/ 6.02*10^23 atoms)= number of atoms of oxygen

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