Question:

How do you calculate the pH at the half-stoichiometric point for titration of 0.22 M HNO2(aq)?

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with 0.01 M KOH (aq)? For HNO2, Ka= 4.3 x 10^-4

i just need to know the steps on this..the right answer should be 3.37

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  1. At the half-equivalence (stoichiometric) point, pH = pKa = -log(Ka);

    pKa = -log(4.3 x 10^-4) = 3.37.

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