How do you calculate this?

Question

1.Calculate the mass of 1.00 ft^3 of gold metal.

2. Calculate the mass of 12.0cm sphere of lead metal

Please explain. Thank you.

Answer 1

density = mass / volume

For#1 mass=volume/density

1 ft = 30.48 cm

1 ft^3 = 30.48cm*30.48cm*30.48cm=28316.846592 cm3

28316.846592 cm3 would be 28316.85 cm3 I think using significant figures.

I am assuming they are giving the density ijn cm^3

using density of gold  19.30 g/cm^3

mass=28316.846592 cm3*19.30 g/cm^3=546515.14 grams

For#2

volume os sphere = 4/3 (pie) radius^3

radius equals 1/2 the diameter

the diameter is 12 cm

pie equals 3.14

so the volume is 904.32 cm^3

using lead density 11.34  g/cm−3

mass=904.32cm^3*11.34g/cm^3=10254.99 grams

The person above accidently used the diamater as the radius.

Answer 2

1..Gold Density = 19.3g/cc

1ft = 12" x 2.54cm/in = 30.48cm.

30.48cm x 30.48cm x 30.48cm = 28,316cc.

28,316cc x 19.3g/cc = 546,500g

= 546.5kg x 2.2lb/kg = 1,202lb  (avoirdupois).

= (1,202lb x 16oz/lb) / 12oz/lb.troy = 1,603lb (Troy).

2..Volume of sphere = 4/3 x π x r³.

= 1.333 x 3.142 x 6cm x 6cm x 6cm = 904.7cc

Density of Lead = 11.34g/cc

= 904.7cc x 11.34g/cc = 10,259g = 10.26kg x 2.2lb/kg = 22,570lb.

Answer 3

need densities of the metals

1. gold is 19.3g/cm^3, but you need to convert to g/ft^3. (19.3g/cm^3)(28316cm^3/1ft^3)=546515.139... since you have only 1ft^3, it stays as 546515.139g or 546.515kg

2. is 12 the radius? if it is you have to do 4/3pi(12)^3, which is 7238.23cm^3

lead is 11.34g/cm^3 and you have 7238.23cm^3 so its

82081.5g or 82.0815kg

make it a good day