How do you do this physics problem?

Question

A car accelerates from 13 m/s to 25m/s in 6.0s. What was its acceleration? How far did it travel in this time? Assume constant acceleration.

Please help me out

Answer 1

a=25-13/6=2m/sec^2, displacement=1/2(2)(6)^2=36 meters.

Answer 2

u = 13 m/s

v = 25m/s

t = 6.0s

Using first equation of motion-

v = u + at

or a = (v-u)/t = (25-13)/6 = 2 m/s2

Using second equation of motion-

s = ut + 1/2 at2 = 13x6 + 1/2 x 2 x 36 = 114 m

Answer 3

acceleration is the change of velocity over change in time

so to find the change in velocity, you do 25 - 13 = 12

the change in time is 6 seconds

So 12/6 = 2 m/s^2