How do you expand (3x-5)^2?

Question

How do you expand (3x-5)^2?

Answer 1

Since u are squaring a binomial, u have to do it like so:

(3x-5)(3x-5)

After that, u just FOIL them together

FOIL is multiplying first terms, outer terms, inner terms, and then last terms.  I hope that helps you.  

Answer 2

I don't know what the sign before the two is

Answer 3

9x^2-30x+25

Answer 4

its 3x times 3x + (3xtimes -5) +(3x times -5) + (-5 times -5)

so itll be 9x^2 + -15x+ -15x + 25

so after all that itll be (9x^2-30x+25)

Answer 5

(3x-5)^2

=(3x-5)(3x-5)

=(3x)(3x) + (3x)(-5) + (-5)(3x) + (-5)(-5)

=9x^2-15x-15x + 25

=9x^2 - 30x + 25

Answer 6

this website saved me during my college algebra class and i'm sure it will help you.

www.myalgebra.com

just type in the algebra problem push submit and boom! you have your answer

oh and the answer is

9x^2-30x+25

just foil it.

multiply

First numbers

Outer numbers

Inner numbers

Last numbers

pairs get positive signs

Answer 7

(3x-5)(3x-5)

Answer 8

(a + b) ^ 2 = a^2 + 2ab + b^2

Answer 9

(3x-5)(3x-5) =

9x^2 - 15x - 15x + 25 =

9x^2-30x+25

Answer 10

9x^2 - 30x + 25

Answer 11

Expand it below:

Let  (3.x-5)^2 is (x+x+x-5)(x+x+x-5)

Answer 12

9x^2 + 25 - 30x

Answer 13

(3x-5)(3x-5)= (3x-5)^2

Answer 14

(3x-5)^2

= (3x-5)(3x-5)

= 9(x^2) - 15x - 15x + 25

= 9(x^2) - 30x + 25