How do you factor 4x^3+12x^2+5x-6?

Question

gawk what to do?

Answer 1

u add the ^3 and the ^2 to get ^5

then u add 4x, 12x, and 5x to get 21

then ur answer is    

21x^5-6

Answer 2

4x^3 + 12x^2 - 30 divide by two

2x^3 + 6x^2 - 15

2(x^3 + 3x^2) = 15 not negative cz its on the other side of the equation

lol thats i could do

maybe

2x^2(x + 3) = 15

then

x+ 3 = 15/ 2x^2

x = (15 / 2x^2) -3

x =(15 - 3 ( 2x^2)) / 2x^2

x= (15 - 6x^2)/ 2x^2

omg am going around in circles

Answer 3

it's impossible the last digit is a -6 and none of the other ones are a negative?

Answer 4

mayb x(4^2+12x+5)-6 mayb im prolly wrong i havent factored since school

Answer 5

What???

Answer 6

I like turtles

Answer 7

btch do your own homework? Use the common sense and listen to the teacher this time.

Answer 8

if the -6 is not an exponent than you need to remove all of the like terms which is only x. now you have x(4x^2+12x-1) beyond this i don't see anything else you could do because that doesnt factor down anymore.  

Answer 9

first find the factor they they all have in common, then put that number out. and you just keep doing the same until you can't continue

Answer 10

4x^3+12x^2+5x-6

(4x^3+12x^2+5x)-6

x(4x^2+12x+5)-6

x(2x+5)(2x+1)-6