How do you factor 5x^2=5x+60?

Question

How do you factor 5x^2=5x+60?

Answer 1

5x^2=5x+60

Subtract the 5x and 60 from both sides.

You are left with: 5x^2-5x-60

Multiply 5 by -60.

5 times -60= -300

Now find what multiplies to get -300 and adds to get -5.

This is 15 and -20.

Now the equation is: 5x^2+15x-20x-60.

Factor the first two and last two terms.

(5x^2+15x) You can factor out: 5x.

You are left with (x+3). Now you are going to factor the last two terms:

Ok, so now you are going to factor (-20x-60). You can factor out -20. You are again left with (x+3).

You would think that the factored version of your original equation is (x+3)(x+3) but it's not.

So, what your going to do is take the first (x+3). Now, look at what you factored out of the two equations. 5x and -20.

So the factored version of your equation is (5x-20)(x+3)... See how I got that. It works every time. Now a way to check your work is to multiply the two terms.

Multiply (5x-20) by (x+3). You can do this by using the FOIL method. As you can see, the result is the original polynomial.

Good luck with your future problems.

Answer: (5x-20)(x+3)

Answer 2

5X^2 - 5X - 60 = 0

5( X^2 - X - 12) = 0

5 ( X - 4 ) ( X+ 3 ) = 0

that is your answer to factorize. but, if you have to solve for x

5x - 20= 0

5x = 20

x = 20/5

x = 4

OR 0R 0R

X + 3 = 0

X = -3

When you substitute you will see that x is equal to -3.