Question:

How do you factor a problem with X^4 in it?

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X^4 -3X^3 + X -3

and

X^3 -1

are the problems

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  1. X^4 -3X^3 + X -3

    factor by groupign first and last 2 terms together

    = x^3(x-3) +1(x-3)

    = (x-3)(x^3+1)

    now factorign that last bracket as it sis a sum of 2 cubes

    =(x-3)(x+1)(x^2-x+1)

    X^3 -1 differnce of 2 cubes

    = (x-1)(x^2 +1x +1)


  2. OK.. Take a look at this.. X^4 can be split into X^2 and X^2

    3 Is a Prime number, so is only divisible by itself and 1

    so one half of the factored equation will be (X^2-3)

    Take this out of the equation and you are left with (X^2+X)

    (X^2-3)(X^2+X) = X^4 -3X^3 + X-3

    X^3-1 can't be broken down, the only factor you can get out of it is 1

  3. i think you have to combine like terms.  

  4. I'm not so sure what you're talking about but let me give you an example

    (x)^2+b+x^2+y

    first multiply x times x

    the problem is now x^2+b+x^2+y

                                                                    

                                          

    Notice how there are two x squareds?

    Combine like terms

    2x^2+b+y

    The question is now factored

    I hope this helps :)

  5. (x^4) - (3*x^3) + x - 3

    divide this into 2 parts

    (x^4) - (3*x^3)      and        + x - 3

    now, greatest common factor

    x^3 (x -3)   and +1 (x-3)

    and now you have common factor (x-3)

    so, factors are:

    (x^3 +1) and (x-3)

    x^3 -1

    (x-1) ( x^2 +1x +1)

    the first part (x-1) you get by taking 3rd root of each value separately (x^3 --> x, and 1--> 1).

    the second part: the first value (x^2) is the value of the first value (x) in the first factor (x-1) squared. the second value (+1x) is the negated product of -1 and x (from x-1). the last is the square of the second value, -1. so -1*-1=1.

    now help me?

    my question: how to solve 2^x + 2^-x = 5. find x.  

  6. X^4 -3X^3 + X -3

    take x^3 common from first two term

    = x^3(x-3) +(x-3)

    = (x-3)(x^3+1)

    2) x^3-1

    can be written as

    = x^3-1^3

    expand using the formula

    (a^3-b^3) = (a-b)(a^2+ab+b^2)

    = (x-1)(x^2+x+1)

  7. it will be useless but like this

    X^4 ( 1-3x^(-1) + x^ (-4) -3 / X^4 )

    but this one will be useful:

    x^3(x-3) +(x-3)

    (x-3)(x^3+1)

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