How do you factor quadratic equations?

Question

I can't factor this ones

2x^2+5x+3

I know how to factor ones which only begins with X.

But I don't remember how to factor ones that begin with a number.

Please help.

Also how would you solve this one?

5x^2=5x=60

Answer 1

your first one is

(2x+3)(x+1)

second

you can say 5x=60 simply solve because if a=b=c then b=c tada

Answer 2

It's easy. You can do it with a little practice.

1.First multiply the coefficient of x^2 and the last number. Suppose you got a.

2x^2 + 5x +3                2*3=6

2.Then think of two numbers whose sum is equal to that of the coefficient of x and when they are multiplied gives a.

        Here the numbers are 2 & 3. (2+3=5 & 2*3=6)

   Writing the equation as 2x^2 + (2+3)x + 3

                                  = 2x^2 + 2x + 3x +3

                                  = 2x(x+1)+3(x+1)

                                 = (2x+3)(x+1).

  5x^2 + 5x = 60

  x^2 + x -12 =0       (dividing both sides by five)

=> x^2 +4x -3x -12 =0

=> x(x+4) - 3(x+4) = 0

=> (x+4)(x-3) = 0

=> x = 3 or -4.

If you have any confusion ask here.

Answer 3

2x^2+5x+3

(2x + 3)(x + 1)

5x^2=5x=60

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