How do you find the domain for this function.?

Question

I forget how to do this problem so if somebody could explain the steps to me that would be great. f(x)=(4x-2)/(x+5)

I am just looking for the domain.

Please and thank-you =D

Answer 1

Hey why dont you go do your own homework!!!!

Answer 2

The domain consists of all the values of x for which the function f(x) is defined.

In this particular case, the function has a value that can be calculated (ie the function is defined) for all the real numbers except x = -5.  This is because when x = -5, the denominator evaluates to 0 and if you graph the function, that would give you a vertical asymptote at -5, so the function is not defined there.

There are a number of ways you can express the domain.

You can use the open and closed interval notation.

To refresh your memory if you see an interval represented as

(a,b) that is an open interval which includes everything between a and b, but not a and b themselves. If you see something like [a,b] )with square brackets, that is a closed interval and does include its endpoints a and b.

So to represent the domain of your function using interval notation you can say

the domain is (-oo, -5) U (-5, oo)  where I'm using oo to represent infinity and U to be the union sign. *

You could also say that the domain is R \ {-5}  meaning that the domain is the set of real numbers (represented by R) minus (represented by the backslash) the set containing the value -5.

*(You use the open intervals because it shows that the first part of the domain runs from -oo to -5, but neither of them are in the domain and then the second part of the domain runs from -5 to +oo, but again neither of them are in the domain.)

Hope this is of some help.

Answer 3

Domain is X

Range is Y

Answer 4

not sure

Answer 5

The domain of a function is the set of numbers for the variable (in this case, _x_) that will give the function a value. For the function f(x)=(4x-2)/(x+5) any value of _x_ will give a value of f(x) except that which makes the denominator zero. The denominator is x+5 , which is zero for x=-5, so the domain of f(x) is all numbers except -5.

Answer 6

Domain is the value of x if I'm not mistaking..

and so there is a vertical asymptote at x=-5 correct?

cuz x+5(can not equal)0 and x can not equal -5.

So the domain is x=ALL REAL #'s Except -5

hope I helped

email me [e-mail] w/ more q's if u've got them!