How do you find the limit of x-->+infinity of (5x^2 +x)^1/2 divided by (10x^2 + 7)^1/2?

Question

x-->+infinity of (5x^2 +x)^1/2 divided by (10x^2 + 7)^1/2?

Answer 1

divide top and bottom by x

bringing x inside the ( )^1/2 gives x^2

(5x^2 + x) / x^2 = 5 + 1/x

(10x^2 + 7) / x^2 = 10 + 7/x^2

so, now we need to find lim sqrt(5 + 1/x) / sqrt (10 + 7/x^2)

"plug in" infinity for x and remember that y/infinity = 0

5 / 10 = 1/2

Answer 2

You need to start with the operations, that are inside the parentheses first.

Answer 3

ouch, math makes my brain hurt.

this should help.

http://www.freemathhelp.com/find-limit.h...

Answer 4

You find the limit by placing this question on the Mathematics section!

I make it 0.707, but it is over thirty years since I did this at school.