How do you find the reciprocal of a graphed function?

Question

There's a little picture of a graphed function in my math textbook (no equation, unfortunately), and I need to graph y = 1/f(x). How would I go about doing such a thing?

Answer 1

its pretty hard to know what your talking about on a computer, and besides i was ba din algebre,

i think you have to plug in what X is from the graph into y=1/f(x<--)

and then do the same for y.

n solve for "f"

if im wrong sorry. as i said before, its hard to understand  

Answer 2

Well to start off any place that f(x) = 0 will be a vertical asymptote. The asymptote will tend to positive infinity if f(x) approaches 0 from being positive and the reverse if it approaches from being negative. I'm not sure about other features

Answer 3

Open up your math book and do your own homework

Answer 4

If you take Sin, cos and tan for example, the graphic reciprocal and mathematical reciprocal of these are cosec, sec and cot respectively. To work out where the points are on the graph you just (1/) the RHS. Take Sin for example, if we take the point on a sin graph y=sin30 then the reciprocal of the x co-ordinate, as sin30 =1/2, is obviously 2 so the point is moved up to 2  and we go forward to y=sin45, 1, the reciprocal of this point is 1 as 1/1=1 :P now take sin 150, 1/2, reciprocal 2. If we join up the points in the same manner as the original sin graph but place asymptotes when y=0 the we get the reciprocal or the graph which is upside down , a series of semi circles which tend to infinity where y would normally equal .

P.S. never ignore a Q as you MAY need to have covered it for the exam...

I hope this hopes, if not a bit long winded, i hope very helpful