Question:

How do you get 2e^(i(9pi/10)) (exponential form), into points to be shown on the argand diagram?

by  |  earlier

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Hey, can you please show me how to do this?

Thanks

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  1. Recall that e^iΘ = cos Θ + i sin Θ

    so e^i(9π/10) = cos 9π/10 + i sin 9π/10

    Now 2 times it  just equals

    2cos 9π/10 + 2i sin 9π/10

    and that's the rectangular coordinates for 2e^(i(9π/10)

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