How do you graph x² ≤ 0 on a number line?

Question

i need help with this its on my homework and idk how to do it!

Answer 1

It's a single point at x = 0.

Answer 2

You place a dot at 0 and that's it. x^2 can never be less than zero.....unless x = i, but I don't think you are dealing with imaginary numbers here.  

Answer 3

For graph...

Draw a parabola (curve) that with a minimum (complete bottom of it) at (0,0), then you know the rest, I'm sure! (It's a parabola because of the x^2)

Since it is less than AND equal to zero, erase the line (all of it) on the right side of the y-axis...and at (0,0), make a round, dark, filled in circle (If it was just x^2<0, you would have placed a circle outline here)

http://www.math.utah.edu/online/1010/par...  <--erase everthing on this to the right of the y-axis...

FOR # LINE:

Place a round circle at the point 0...why would ur teacher want this on a # line anyways?

Answer 4

do not trust these first three answers.

to graph this first do the = and from that determine <

because this is an "or" question to read the mathematical statement as a sentence:  X such that X square is less than or equal to zero.

if X square = 0  the X is 0

if X square is less than zero  .... reason this... an number when squared is going to be positive so x square has to be positive and therefore can not be less than zero

so x has the be one one point 0 on a number line....

Answer 5

it's a blank number line.

Answer 6

It is a parabola that's minimum is lower than the vertex 0.

so Imagine a big "U" that the bottom of the "U" is below the points (0,0)

Answer 7

That's impossible. I don't think you can graph a parabola on a number line.

Answer 8

man im glad i graduated already