Question:

How do you integrate this?

by  |  earlier

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= -2x*e^x *dx

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  1. ∫ - 2x e^x dx =

    this is a classic by parts integral:

    let

    e^x dx = dv → e^x = v

    - 2x = u → - 2 dx = du

    then, integrating, you get:

    ∫ u dv = u v - ∫ v du →

    ∫ - 2x e^x dx = - 2x e^x - ∫ e^x (- 2) dx =

    - 2x e^x + 2 ∫ e^x dx =

    - 2x e^x + 2e^x + C

    in conclusion,

    ∫ - 2x e^x dx = 2e^x (1 - x) + C

    I hope it helps..

    Bye!

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