How do you set this math equation equal to zero?

Question

(x+1) ^-1 = x^-1 + x

if that doesn't make sent it means like to the power of -1.

helpness?

Answer 1

Subtract what is on the right hand side of the equation from both sides of the equation.

(x+1)^-1 - x^-1 -x = 0   <<<<< Is this what you want.  If so, stop.  If not, continue.

1/(x+1) - 1/x - x = 0        The least common denominator is (x)(x+1)

Multiply both sides of the equation by (x)(x+1)

x - (x+1) - x^3 - x^2 = 0

-1 - x^3 - x^2 = 0

Multiply both sides of the equation by -1

x^3 + x^2 + 1 = 0   <<<<< or is this what you want?

Answer 2

move everything to one side, switch signs when you move to the other side, and that equals 0

(x+1) ^-1 - x^-1 - x  = 0

Answer 3

you just have to put everything on the right side onto the left side .

when you do this . everything has a reverse effect ..

so

it becomes

(x+1)^-1 -x^-1= x

and then

(x+1)^-1 -x^1-x=0

Answer 4

simple

move the right hand terms to left with a change in sign.

Answer 5

i agree with harique

Answer 6

Adding opposites will set it equal to zero.

Raising to the power of -1 just flips it over into a fraction.

x ^ -1 just means 1/x

if you need to get rid of negative exponents, I would write :

1/(x+1) - 1/x - x = 0

Good luck to you !

Answer 7

(x+1)^-1 - x^-1 - x = 0

Answer 8

the equation is invalid, since...

(x+1)^-1 = x^-1 + x

=> 1/ (x+1) = 1/x + x

=> 1/(x+1) = (1+x^2)/x  [LHS != RHS]

if that doesn't make sent it means left hand side not equal to right hand side

I am thinking too complicated. please ignore whatever it is I said above.