How do you simplify this expression (Algebra) Help!!!?

Question

Simplify the expression:

12t^2 + 12t + 3

over

4t^2 - 1

I know that the GCF in the numerator is 3, but I am so lost!!!!

Answer 1

both jaycee and jjj have the correct answer...jjj has distributed the 3 which may or may not be necessary depending upon how your professor wants the solution....i personally would leave it factored...but that's just me

Answer 2

12t^2+12t+3

-------------------

   4t^2-1

3(4t^2+4t+1)

-------------------

    4t^2-1

3(2t+1)(2t+1)

--------------------

  (2t-1)(2t+1)

3(2t+1)

-----------

(2t-1)

6t+3

-------

2t-1

Answer 3

12t^2 + 12t + 3

----------------------

4t^2 - 1

= 3(4t^2 + 4t + 1)

-------------------------

      4t^2 - 1

= 3(2t + 1 )(2t + 1)

---------------------------

(2t + 1)(2t -1)

= 3(2t+1)

-------------

    (2t-1)

Answer 4

12t^2+12t+3

-------------------

4t^2-1

3(4t^2+4t+1)

------------------

4t^2-1

(2t+1)(2t+1)

===========

(2t-1)(2t+1)

2t+1/2t-1