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How do you solve 3x-4(x+2)4?

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How do you solve 3x-4(x+2)4?

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  1. [3x-4][x][+2][4]

    = [-12][x][+2][4]

    = [-24][4]

    = -96

    BTW, x is times or it is an x?


  2. Foil the first two and then multiply by for.

    FOIL = First terms, outside terms, inside terms, last terms

    (3x - 4)(x +2) = (3x)(x) + (3x)(2) + (-4)(x) + (-4)(2) =

                           4(3x^2 + 2x-8) = 12x^2 +8x -32

  3. BOMDAS

    1. Brackets 4(x+2) = 4x+8

    2. OMD 4times 4x+8 = 16x + 32

    3. AS 3x +16x = 19x

    Answer is 19x + 32
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