How do you solve for X? x2-6x-7=0?

Question

How do you solve for X? x2-6x-7=0?

Answer 1

well, first u calculate delta"D"

D=(-6)^2-4x(-7)x1=36+28=64=8^2

then, X1=[ -(-6)+8]/2x1=14/2=7

        X2=[ -(-6)-8]/2x1=-2/2=-1

then X^2-6X-7=(X-7)(X+1)

Answer 2

(x=7, -1

Answer 3

x^2 - 6x - 7 = 0

(x-7)(x+1)

So x = 7; x = -1

7^2 - (6)(7) - 7 = 0

49 - 42 - 7 = 0

0 =0

(-1)^2 - (6)(-1) - 7

1 + 6 - 7 = 0

0 = 0

So, they check.

Answer 4

x^2-6x-7=0

a=1  b= -6  c=-7

6 (+/-) √36-4*1*(-7)

---------------------------

        2*1

6(+/-) √64

--------------

      2

6(+/-)8

----------

     2

6+8              

-----    =7        

  2

OR

6-8

-----  =  -1

2

Answer 5

(x+1)(x-7)=0

x+1=0   x-7=0

x=-1      x=7

Answer 6

1. x^2-6x-7=0

x^2-7x+x-7=0

x(x-7)+1(x-7)=0

(x-7)(x+1)=0

x-7=0 or x+1=0

x=7 or x=-1

2. 6x^2-x-2=0

6x^2-4x+3x-2=0

2x(3x-2)+1(3x-2)=0

(3x-2)(2x+1)=0

3x-2=0 or 2x+1=0

3x=2 or 2x=-1

x=2/3 or x=-1/2

Answer 7

factor it to

(X-7) (X+1)

X=7 X= -1