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How do you solve for t? 3000= 2028.75^(4t)?

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How do you solve for t? 3000= 2028.75^(4t)?

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  1. 3000 = 2028.75^(4t)

    Take the log of both sides:

    log 3000 = log 2028.75^(4t)

    Log laws allow you to bring out that 4t in front of the log:

    log 3000 = (4t) log 2028.75

    log 3000 / log 2028.75 = 4t

    t = (log 3000 / log 2028.75) / 4

    t = (log 3000 / 4 log 2028.75)

    t ≈ 0.2628


  2. log 3000 = (4t) log 2028.75

    4t = log 3000 / log 2028.75

    4t = 1.05

    t = 0.2625
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