How do you solve for time in d=Vit +1/2at^2?

Question

How do you solve for time in d=Vit +1/2at^2?

Answer 1

its a pure quadratic equation in t...so u can .. if uwish factorize it or use the formula for roots and get the values for t

The formula is if the quadratic is ax^2 + bx +c = 0 then

x=[-b+(b^2 - 4ac)^0.5]/2a and [-b-(b^2 - 4ac)^0.5]/2a

Answer 2

It depends on the quantities given

If given the distance(d) acceleration(a) and ZERO initial velocity(Vi=0) it is very easy

the equation becomes----------> square.root(2d/a) = t

Since Vi=0           Vit becomes ZERO so thats fairly simple

if NOT then you will have solve through a quadratic formula

in which case

t = ( -(a/2) + Sqr.root( ((a/2)^2) + (4Vid) ) ) / ( 2Vi )

and also

t = t = ( -(a/2) + Sqr.root( ((a/2)^2) + (4Vid) ) ) / ( 2Vi )

Since its a quadratic equation so t will have two values, the real one would be the one with the positive sign