Question:

How do you solve the equation: 0=x^3 - x^2 -4x +4?

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How do you solve the equation: 0=x^3 - x^2 -4x +4?

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  1. First of all, the x^3 - x^2 makes x^1 which is just x or 1x. Subtract 4x and you have -3x. Add 4 to make 1x or just x. So x = 0.


  2. Greetings,

    x^3 - x^2 - 4x + 4 = 0

    x^2(x - 1) - 4(x - 1) = 0

    (x^2 - 4)(x - 1) = 0

    (x - 2)(x + 2)(x - 1) = 0

    x = 2 or x = -2 or x = 1

    Regards

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