How do you solve the following radical?

Question

√x-2 - √2x+3=0

Answer 1

the given can be re-written:

sqrt(x - 2) = sqrt(2x + 3)

x -2 = 2x + 3   (squared both sides)

- 2  = x + 3       (subtract x for both sides)

- 5  = x  

but when checking, subtitute x = - 5 back into the original equation, we have sqrt(-7) and sqrt(-7) is not a real number.

Therefore, the equation has no solution.

Answer 2

Try to resolve it backwards, figure out x and square it,

Hope it helped!

Answer 3

(√x - 2) - (√2x + 3) = 0 :

(xsquared - 4) - (2x + 9) = 0

-3xsquared + 5

-3xsquared = -5

xsquared = 5/3

x = √5/3

Answer 4

square the equation

x-2-2x+3=0

-x+1=0

-x=-1

x=1