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How do you solve the linear equation finding x y intercepts? the problem is this; 3x-2y= -6?

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How do you solve the linear equation finding x y intercepts? the problem is this; 3x-2y= -6?

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  1. need second equation for x y finding

    p.s. in this equation y=1,5(2+x)


  2. Find x:

    3x-2y=-6

    3x=2y-6

    x=(2y-6)/3

    Substitute into equation and find y:

    3 x (2y-6)/3 - 2y = -6

    2y-6 - 2y = -6

    -6=-6

    y=0

    Find x:

    3x-2y = -6

    3x-2(0) = -6

    3x= -6

    x = -2

    y=0

    x=-2

    The coordinates are: (-2,0)

  3. x intercept is when y = 0

    y intercept is when x = 0

    so the answers are:

    x-intercept = -2

    y-intercept = 3

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