How do you solve the problem below?

Question

(x+6)/(x+1)=(x^2+x-2)/(x^2+5x+6)

Answer 1

To do this, you need to first get rid of the division. To do this, cross multiply. That means you will multiply the top left of the equation by the bottome right, so x+6 times x^2 +5x+6. Do the same thing for the other two by multiplying x+1 times x^2+x-2. After you have one so, set bothe sides equal to each other and solve. Hope this helps!

Answer 2

Cross multiply (multiply the bottom number to the opposite side)

You end up with this:

(x+6)*(x^2+5x+6)=(x^2+x-2)*(x+1)

Then you FOIL and solve for x

Answer 3

If you factor the right side of the equation, you will find a common term in the numerator and the denominator. You can cross these out because they cancel out and you will be left with something like this:

(x+6)/(x+1) = (x something)/(x something else)

Then you need to cross multiply the remaining equations:

(x+6)(x something else) = (x+1)(x something)

distribute multiply each side of the equation:

something x^2 + something x + something = something else x^2 + something else x + something else

then subtract the right hand equation from the left:

(something - something else) x^2 + (something - something else) x + (something - something else) = 0.

At this point, you should be able to use the quadratic formula (or other algebraic methods) to solve for X.