How do you solve these problems?? ?

Question

Write the standard form of the equation of the line that is parallel to the graph of the given equation and passes through the point, with the given coordinates.

1. y=(1/3)x-2; (-1,6)

Answer 1

To start, we know that a parallel line will have the same slope (1/3) as the original equation. Then, you just have to use the point - slope formula...

y-6=1/3(x-(-1))  cancel the negative

y-6=1/3(x+1) multiply by 1/3

y-6=1/3x+1/3  add 6 to finish

y=1/3x+6 1/3    or 19/3 if you prefer instead of 6 1/3.