How do you solve these problems?

Question

R + 5/6 = -3/12

y - 8 ≥ 0

The additive inverse of 3/4 and 0.

Determine whether the lines are parallel: 1/2x-5y=3 and -2x+10=1

Solve E=mc2 for m.

Answer 1

y less/equal 8

e=mc2

square root of e/c

Answer 2

go to hotmath.com look up the book you use, then the page number that should help you.  

Answer 3

You change 5/6 so the denominator is 12 so then it would change to 10/12.

R = -3/12 - 10/12

R = -13/12

y > or = to  8 (you add 8 to both sides)

i dont understand what you put for the 3rd one

Is there suppose to be a y after the 10 in the 2nd line. If there is then it'd be 2x +10y = 1. Multipy the first equation by to get rid of the fraction x -  10y = 6 and -2x + 10y = 1. These line are not parallel, if they were their slope (x) would be the same.

E/c2 = m

Answer 4

1) r + 5/6 = -3/12

r + 10/12 = -3/12

r = -13/12

2) y >= 8

3) Additive inverse of 3/4 is -3/4

Additive inverse of 0 is 0

4) (1/2)x - 5y = 3

5y = (1/2)x - 3

y = (1/10)x - 3/5

Slope = 1/10

-2x + 10y = 1

10y = 2x + 1

y = (1/5)x + 1/10

Slope = 1/5

They are not parallel.

5) E = mc^2

m = E / c^2