Question:

How do you solve this alegebra problem?

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1/4 + 1/3 (5x + 2) = -2

I keep getting -13/20 but when I check the answer with the back of my book it's wrong.

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  1. 1/4 + 5x/3 +2/3 = -2

    3/12 + 20x/12 + 8/12 = -24/12

    20x = -24 - 8 - 3

    20x = -35

    x= -35/20

    x= -7/4


  2. 1/4 + 1/3(5x+2)=-2

    subtract 1/4 from both sides

    1/3(5x+2)= -2 1/4

    divide 1/3 from both sides

    5x+2= - 6 3/4

    subtract 2 from both sides

    5x = - 8 3/4

    divide 5 from both sides

    x= - 1 3/4

  3. -7/4

    => 1/4 + 1/3 (5x + 2) = -2

    => 1/3 (5x + 2) = -2 - 1/4 = -8/4 - 1/4 = -9/4

    => 1/3 (5x + 2) = -9/4

    => [1/3 (5x + 2) = -9/4]* 3

    => 5x + 2 = -27/4

    => 5x = -27/4 -2 = -27/4 - 8/4 = -35/4

    => 5x = -35/4

    => [5x = -35/4]/5

    => x = -35/4 * 1/5 = -35/20 = -7/4


  4. Yes, your answer is incorrect.

    Multiple both side by 12 to get rid of the fractional forms.

    3 + 4(5x + 2) = -24

    Now expand, isolate and solve.

    3 + 20x + 8 = -24

    20x = -35

    x = -35/20 = - 1 3/4

  5. combine like terms:

    1/4 +1/3(5x +2) = -2

    1/4 +5/3x +2/3 = -2

    5/3x + 3/12 + 8/12 = -2

    5/3x +11/12 = -2

    subtract 11/12:

    5/3x = -2 11/12

    simplify fraction:

    5/3x = -35/12

    multiply by 3/5:

    x = -35/20 = -7/4

    answer:

    x = -7/4 or -1 3/4

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