How do you solve x^2 - 5x - 6 =0?

Question

I'm taking a math class and I can't remember how to solve these type of problems can someone show me how to do this with the steps. Thank You!

Answer 1

Factor it first

x^2 - 5x - 6

= (x - 6)(x + 1) = 0

so x = 6 or x = -1

Answer 2

Open up 2 brackets (        )(        )

Put x's in: when multiplied these give the x^2   (x      )(x      )

Now think of 2 numbers that when multiplied give 6

and when added or subtracted give 5                       (x     1)(x     6)

Now for the signs, you need -6 so you need one + and 1 -

To get the -5, it has to be -6 and +1

                                                                      (x+1)(x-6)

To solve, put each bracket =0   x+1=0  x-6=0

and get the x,s on their own      x=-1   x=6

Answer 3

x^2 - 5x - 6 = 0

x^2 - 6x + x - 6= 0

x(x-6) + 1(x-6)=0

(x+1)(x-6)= 0

=> x = -1; x = 6 .

while solving these type of questions you have to calculate the factors required to solve the problem.

In  the above problem you have to look at  6( product) and 5x(sum).Finding factors means  you have to get 2 numbers such that their product is 6 and their sum is 5.

well if it was

(x+6)(x-2) = - 7

x^2 - 2x + 6x - 12 + 7= 0

x^2 + 4x - 5 = 0

x^2 + 5x - x - 5 = 0

x(x +5) - 1(x+5) = 0

(x-1)(x+5) = 0

x = 1 ; x= -5

we r writing  =0 (example : x^2 - 5x - 6 = 0) because then only it is called an equation .

Answer 4

Factor:

(x - 6)(x + 1) = 0

x = 6 ; x = -1

Answer 5

x^2 - 5x - 6 =0

w3er32 + 123423 - =023423/325err

= 2

Answer 6

(x-6)(x+1)=0 which gives u x=6 and x=-1