How do you work this problem (x-4y)(2x +y)?

Question

How do you work this problem (x-4y)(2x +y)?

Answer 1

You will use the FOIL method.  First, Outside, Inside, Last.

(X-4Y)(2X+Y)

First.

X x 2X = 2X squared.

Outside.

X x Y  = XY

Inside.

-4Y x 2X = -8XY

Last.

-4Y x Y  = -4Y squared.

So,  2X squared + XY - 8XY - 4Y squared.

2X squared - 7XY - 4Y squared is your answer!

Answer 2

(x-4y)(2x+y)

2x^2-8xy+xy-4y^2

2x^2-7xy-4y^2

Answer 3

Use the Foil method. FOIL stands for First, Outer, Inner, & Last. It is a way to guarantee each term in the problem will be multiplied to all the others outside its parentheses.

Multiply the first terms in each set of parentheses.

(x)(2x)=2x^2

Next, multiply the terms on the outer edge of the parentheses.

(x)(y)=xy

Now multiply the terms on the inner edge of the parentheses.

(-4y)(2x)=-8xy

Finally, multiply the last term in each set of parentheses.

(-4y)(y)=-4y^2

Now we have the equation

2x^2+xy-8xy-4y^2

Combine all like terms.

2x^2-7xy-4y^2

That's your final answer.

Answer 4

(x-4y)(2x+y) = 2x^2-8x*y+x*y-4y^2 = 2x^2-7x*y-4y^2

Answer 5

I assume you want them multiplied. Use the method of FOIL, where you multiply the First terms of the parentheses, then the Outside, then the Inside, and finally the Last terms:

(x - 4y)(2x + y)

F = First = x * 2x = 2x^2

O = Outside = x*y = xy

I = Inside = -4y * 2x = -8xy

L = Last = -4y * y = -4y^2

2x^2 + xy - 8xy - 4y^2 (combine like terms)

2x^2 - 7xy - 4y^2 <===ANSWER