How do you write an equation for a relation when given a set of points? (-3,10) (-2,5) (-1,2) (0,1) (1,2) ?

Question

the rest of the points are (2,5) and (3,10)

{ALL POINTS}

(-3,10) (-2,5) (-1,2) (0,1) (1,2) (2,5) and (3,10)

Answer 1

The differences in the consecutive y values are 5, 3, 1, -2, -3, -5

The differences in these are -2, -2, -2, -2 , -2, -2 so when these second differences are equal you have a quadratic so x^2 is in there.  Notice then that the y number is always 1 higher than the x number squared.  That should give you the clues you need.