How do you write an equation of a line that contains the points(1,6) and (-3,10)?

Question

thanks in advance

Answer 1

u use the expression to find the equation of the line.

y-y1= m(x-x1)

y & x are variable

m is gradient

x1 & y1 are the numbers on the line given to u.  in this case either use (1,6) or (-3,10)

to find m = y2-y1/x2-x1

so  m = 6 -10/1-(-3) = -4/4 = -1

therefore  y-y1= m(x-x1)

y - 6 = -1 (x - 1)

y = -x + 7

Answer 2

y = -x + 7

The equation is

y - 6 = m(x - 1)  where the slope m = (10 - 6)/( -3 -1) = -1

So   y = -x + 1 + 6 = -x + 7