How is a function with char array return type declared in C?

Question

How is a function with char array return type declared in C?

Answer 1

Ok, since you've asked about the declaration and not definition, here is how a function with char array as a return type is declared:

char* foo(arg..);

(where *arg* is the argument you want to pass to this function. In case of no argument, it won't be needed over there.)

As for the example of how to define a char array returning function. here is an example of that sort, for your help:

/* Program for returning no. of names from database */

char list[10];   //global declaration of the character array.

char* foo(int number);

int main() {

......

}

char* foo(10) {

/*sort & read names */

return list;

}

hope that this will quench your search for the answer :)

Answer 2

You can do this:

char* myfunc(int x);

Or this:

char[] myfunc(int x);

To answer the question I assumed you want a function that takes one int, and retuns a char array.  If the input args are different, modify accordingly.  For example: char* myfunc(); -- if there are no input args.

Answer 3

char somefunction(<parameters>) {

}

just like any other function