How long would it take a 200 lb. man to hit the ground if he fell 300 ft?

Question

How long would it take a 200 lb. man to hit the ground if he fell 300 ft?

Answer 1

First of all the equations you will want to use to get the time is the equation for constant acceleration in the y-direction

y(final position)=y(initial position)+velocity(initial)*time+.5*acc.... note that velocity initial will be 0

You will need to convert your given values into meters and kg to use them in the equation

Now acc. can be found with the previous poster, that all falling objects accelerate at 9.81 meters/sec.^2

and that will be all you need to find you last missing variable, time.

Answer 2

If you drop a balled up piece of paper and a book by holding it up in front of you they would both hit the floor about the same time, pending air resistance and mass that would interfere with the object because gravity is a constant. but you can look at the url I am enclosing to help you out.

Answer 3

Weight is irrelevant; all objects are acted upon equally by gravity. Weight, or mass, only is an issue when calculating the kinetic force of the falling object.

The rate of acceleration on Earth at sea-level is 32.174ft per second per second (no, that's not stuttering - seconds squared) until terminal velocity is reached. Terminal velocity is determined mostly by drag and is the speed at which the upward force (the atmosphere) equals the falling force (gravity pulling  the body down) and it can vary. A skydiver in a diving position can attain speeds of almost 200mph but if he goes spread eagle he can reduce his speed to about 140mph.

The math invovled is calculus and it's been 30 years since I've used that stuff. The short answer is:

t = sqrt[distancde/16.1]

or (300/16.1)^ 1/2 (square root)

which is about 4.3 seconds

Answer 4

everything falls at a speed of 9.8 meters per second , but idk exactly how to figure it out

Answer 5

ASSUMING no air resistance, this becomes a freely-falling body and the working formula is

S = VoT + (1/2)gT^2

where

S = height at which the man will fall = 300 feet

Vo = initial velocity = 0

T = time of fall

g =acceleration due to gravity = 32.2 ft/sec^2

Substituting appropriate values,

300 = 0 + (1/2)(32.2)T^2

T^2 = 300 * 2/32.2

T = 4.32 sec.

Answer 6

The weight wouldn't matter as much as the surface area, but we can go ahead and neglect that. On earth, acceleration due to gravity is 9.81 m/s. The 300 feet he fell is equivalent to 91.44m.

The equation you would use is: d= .5 a t²

d= distance

a= acceleration

t= time

91.44 = .5 (9.81) (t²)

18.64 = t²

time= 4.32 seconds