How many atoms of nitrogen are in a 3.7 gram sample of aspartame?

Question

Nitrogen is 14.01 g/mol

Aspartame = C14 H18 N2 O5 (294.304 g/mol)

Answer 1

Get the grams of asparteme into moles. When you have how many moles of aspartame, multiply it by two, since there's two moles of N in one mole of asparteme. Then convert the moles of N into atoms, by mutiplying the moles of N with avogadro's number.  

Answer 2

3.7 grams of aspartame.  To get moles of asp. do 3.7/294.304 which is .0125 moles.  Multiply by 2 to get .250 moles times 6.02 times 10^23 (avogadros number)

This will get you atoms of nitrogen.