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How many atoms will remain after 3 half-lives?

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Beginning with n atoms of an unstable nuclide, how many atoms will remain after 3 half-lives? After 5 half-lives?

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  1. atoms = 0.5^x

    x=#of half lives

    so # atoms = 0.5^3=0.125  or 1/8 after 3 or 1/2*1/2*1/2=1/8

    so # atoms = 0.5^5=0.01325 or 1/32 after 5 or 1/2*1/2*1/2*1/2*1/2=1/32


  2. 1 / 2 = 1/2

    1/2 / 2 = 1/4

    1/4 / 2 = 1/8th of original atoms after 3 half lives.

    1/8 / 2 = 1/16th

    1/16th / 2 = 1/32nd of original atoms after 5 half lives.

  3. After each half-life, the number of atoms is reduced to 1/2 of the number before the half-life. Hence, after 3 half-lifes, the number of atoms remaining is (1/2)*(1/2)*(1/2)*n = n/8. Similarly, after 5 half-lifes, the number of atoms remaining is n/(2^5) = n/32.

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