How many children are standing in a circle if The 8Th child is directly opposite to 20Th child(with equation)?

Question

How many children are standing in a circle if The 8Th child is directly opposite to 20Th child(with equation)?

Answer 1

difference between the two = 12

12+12 (because theyre both half of the circle apart from each other) = 24

24 +2 (accounting for the kids 8 and 20) =26

So 26

Answer 2

let's assume it to be x. then the equation will be like(by equating the two semicircles formed on either sides of child 8 and 20)

    (x-20)+8 = 20-8

=>x = 12+12 =24

hence, no of children in the circle is 24. Do message me if this solution works.

Answer 3

20 - not enough data to say, so we'll have to assume its 20 because its the highest number given in detail. You can't assume anything since no radius or circumference or diameter is given.

Answer 4

24.... 20-8 = 1/2x......12 = 1/2x..... 24 = x

Answer 5

20-8 = c/2

20-8 = 12

12= c/2

12/1 = c/2

1 x c = c

12 x 2 = 24 kids