Question:

How many electrons?

by  |  earlier

0 LIKES UnLike

how many electrons can occupy the fourth shell? fifth shell? someone help me?

 Tags:

   Report

5 ANSWERS


  1. I think the fourth is like 32.  The pattern goes 4,8,18,32.  I;m not sure about the fifth though.


  2. Shell Subshell Orbitals   Electrons

    n = 5    l = 0   m = 0 → 1 type s orbital → max 2 electrons



    l = 1   m = -1, 0, +1 → 3 type p orbitals → max 6 electrons



    l = 2   m = -2, -1, 0, +1, +2 → 5 type d orbitals → max 10 electrons

      

    l = 3    m = -3, -2, -1, 0, +1, +2, +3 → 7 type f orbitals → max 14 electrons

      

    l = 4    m = -4, -3 -2, -1, 0, +1, +2, +3, +4 → 9 type g orbitals → max 18 electrons  

          Total: max 50 electrons!!

  3. The periodic table has a pattern of new rows adding specific numbers of elements: 2, 6, 10, 14. (Look at it, to see what I'm talking about.)

    If you are the pattern-seeking type, you'll say, "hey -- those numbers are all even -- what happens when I halve them?" And the answer is that you get "1, 3, 5, 7."

    That's a general relationship confirmed in quantum mechanics: the N'th shell adds a new "kind" of orbital, and the number of electrons that can occupy this new orbital is twice the N'th odd number.

    Any given shell holds twice the sum of the first N odd numbers. Via induction, you can confirm that this number is 2N².

    "But wait," I hear you ask: "Why doesn't that set of 10 elements show up until row 4? Why doesn't it show up at row 3?" The answer is, because it's no longer the orbital of lowest energy. Nature prefers to fill the 4s orbitals before it fills the 3d orbitals. Them's the breaks.

    "But wait," I hear you ask again. "That block at the bottom has 15, not 14!" That's because there's a hole in the periodic table in group 3, periods 6 and 7. Lanthanum and Actinium probably *should* be taking up those spaces, but instead those spaces needed to hold a big asterisk pointing to the block at the bottom of the table.

  4. The formula for a shell with quantum number n  is 2n^2

    so n=4   2*16=32

         n=5  2*25=50

  5. 1st<<1x2=2

    2nd<2x2x2=8

    3rd<2x2x2x2=16

    4th<2x2x2x2x2=32

    5th<5. x 8=40

    .
You're reading: How many electrons?

Question Stats

Latest activity: earlier.
This question has 5 answers.

BECOME A GUIDE

Share your knowledge and help people by answering questions.