How many liters of 1M HCl solution is needed to dissolve 19 grams of Fe

Question

Fe(s) 2 HCl(aq) → FeCl2 (aq) H2 (g)

Answer 1

Moles Fe = 19 g / 55.847 g/mol = 0.34

the ratio between Fe and HCl is 1 : 2

Moles HCl = 2 x 0.34 = 0.68

V = moles / M = 0.68 mol / 1 M = 0.68 L

Answer 2

2 moles of HCl will be needed for each mole of Fe

19 g Fe / 55.8 g Fe = 0.34 moles Fe

0.33 * 2 = 0.68 moles of HCl

0.68 moles =x liters HCl * 1.06 mole HCl / 1liter HCl

Solving you get x = 0.69 l