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How many liters of water are required to dissolve 1 gram of calcium phosphate?

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knowing the solubility of calcium phosphate = 3.41×10−5 g/L

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  1. 1 gram/3.41 X 10^-5 grams/liter grams cancel and the answer is in liters ...

    = 0.2933 x 10^5 liters = 2.933 X 10^4 liters =29,330liters

    Proof

    (2.933 x10^4 liters )( 3.41 x10^-5grams/liter) = 10.001 X 10^-1 = 1.001 grams

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