How many milliters of 0.400 M NaOH are required to completely neutralize 20.0 ml of 0.200 M HCl ?

Question

Please show me how to do this and the answer:)

Thanks!

Answer 1

M1V1 = M2V2

(.400)V1 = (.200)(20)

Solve for V1.

V1 = (.200)(20)/.400

V1 = 10 mL

Hope I helped!! :)

Answer 2

with complete neutralization that means that the meq of base = meq of acid..therefore at the endpoint

  VacidMacid = VolbaseMbase

20 mL ( 0.2M ) = Volbase ( 0.4 M )

{(20 mL )(0.2M )}/0.4 M = Volbase

the M cancels and the answer is 10 mL of the 0.4 M NaOH solution